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1053444130 = 25257940847
BaseRepresentation
bin111110110010100…
…100100000100010
32201102020111200021
4332302210200202
54124140203010
6252310544054
735051061454
oct7662444042
92642214607
101053444130
114a0707192
1225496802a
1313a33012b
149dca02d4
156273b8da
hex3eca4822

1053444130 has 16 divisors (see below), whose sum is σ = 1896981120. Its totient is φ = 421203952.

The previous prime is 1053444127. The next prime is 1053444163. The reversal of 1053444130 is 314443501.

It is a super-2 number, since 2×10534441302 = 2219489070062913800, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1053444095 and 1053444104.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5367 + ... + 46213.

It is an arithmetic number, because the mean of its divisors is an integer number (118561320).

Almost surely, 21053444130 is an apocalyptic number.

1053444130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1053444130 is a deficient number, since it is larger than the sum of its proper divisors (843536990).

1053444130 is a wasteful number, since it uses less digits than its factorization.

1053444130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43433.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 1053444130 is about 32456.8040632469. The cubic root of 1053444130 is about 1017.5064459182.

Adding to 1053444130 its reverse (314443501), we get a palindrome (1367887631).

The spelling of 1053444130 in words is "one billion, fifty-three million, four hundred forty-four thousand, one hundred thirty".

Divisors: 1 2 5 10 2579 5158 12895 25790 40847 81694 204235 408470 105344413 210688826 526722065 1053444130