Base | Representation |
---|---|
bin | 10011101000000010… |
… | …01110010010101101 |
3 | 1000012022010012111211 |
4 | 21310001032102231 |
5 | 133034310143313 |
6 | 4501303514421 |
7 | 522050012206 |
oct | 116401162255 |
9 | 30168105454 |
10 | 10536412333 |
11 | 4517591597 |
12 | 2060758a11 |
13 | cbbb81115 |
14 | 71d4b65ad |
15 | 41a019e3d |
hex | 27404e4ad |
10536412333 has 2 divisors, whose sum is σ = 10536412334. Its totient is φ = 10536412332.
The previous prime is 10536412321. The next prime is 10536412343. The reversal of 10536412333 is 33321463501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8172702409 + 2363709924 = 90403^2 + 48618^2 .
It is a cyclic number.
It is not a de Polignac number, because 10536412333 - 213 = 10536404141 is a prime.
It is a super-2 number, since 2×105364123332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10536412295 and 10536412304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10536412343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5268206166 + 5268206167.
It is an arithmetic number, because the mean of its divisors is an integer number (5268206167).
Almost surely, 210536412333 is an apocalyptic number.
It is an amenable number.
10536412333 is a deficient number, since it is larger than the sum of its proper divisors (1).
10536412333 is an equidigital number, since it uses as much as digits as its factorization.
10536412333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 31.
Adding to 10536412333 its reverse (33321463501), we get a palindrome (43857875834).
The spelling of 10536412333 in words is "ten billion, five hundred thirty-six million, four hundred twelve thousand, three hundred thirty-three".
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