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10540413431411 is a prime number
BaseRepresentation
bin1001100101100010000110…
…0110010010111001110011
31101022122122112102222211212
42121120201212102321303
52340143231314301121
634230111000230335
72135343161620103
oct231304146227163
941278575388755
1010540413431411
1133a4189659706
12122297716b3ab
135b5c58bc0806
142862317bd203
151342a89c625b
hex99621992e73

10540413431411 has 2 divisors, whose sum is σ = 10540413431412. Its totient is φ = 10540413431410.

The previous prime is 10540413431363. The next prime is 10540413431467. The reversal of 10540413431411 is 11413431404501.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10540413431411 - 234 = 10523233562227 is a prime.

It is a super-2 number, since 2×105404134314112 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10540413421411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5270206715705 + 5270206715706.

It is an arithmetic number, because the mean of its divisors is an integer number (5270206715706).

Almost surely, 210540413431411 is an apocalyptic number.

10540413431411 is a deficient number, since it is larger than the sum of its proper divisors (1).

10540413431411 is an equidigital number, since it uses as much as digits as its factorization.

10540413431411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 10540413431411 its reverse (11413431404501), we get a palindrome (21953844835912).

The spelling of 10540413431411 in words is "ten trillion, five hundred forty billion, four hundred thirteen million, four hundred thirty-one thousand, four hundred eleven".