Base | Representation |
---|---|
bin | 11110101011011111101… |
… | …10011010110100010001 |
3 | 10201202221002000102121221 |
4 | 33111233312122310101 |
5 | 114232341220232423 |
6 | 2124133350045041 |
7 | 136105442054011 |
oct | 17255766326421 |
9 | 3652832012557 |
10 | 1054143524113 |
11 | 3770725a0a39 |
12 | 150372649781 |
13 | 785365cc384 |
14 | 390411abc41 |
15 | 1c649c81e5d |
hex | f56fd9ad11 |
1054143524113 has 2 divisors, whose sum is σ = 1054143524114. Its totient is φ = 1054143524112.
The previous prime is 1054143524041. The next prime is 1054143524123. The reversal of 1054143524113 is 3114253414501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1045696443649 + 8447080464 = 1022593^2 + 91908^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1054143524113 is a prime.
It is a super-2 number, since 2×10541435241132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1054143524123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527071762056 + 527071762057.
It is an arithmetic number, because the mean of its divisors is an integer number (527071762057).
Almost surely, 21054143524113 is an apocalyptic number.
It is an amenable number.
1054143524113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1054143524113 is an equidigital number, since it uses as much as digits as its factorization.
1054143524113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 1054143524113 its reverse (3114253414501), we get a palindrome (4168396938614).
The spelling of 1054143524113 in words is "one trillion, fifty-four billion, one hundred forty-three million, five hundred twenty-four thousand, one hundred thirteen".
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