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10542124441 is a prime number
BaseRepresentation
bin10011101000101110…
…00000110110011001
31000012200212102001101
421310113000312121
5133042240440231
64502030151401
7522146402452
oct116427006631
930180772041
1010542124441
11451a833142
122062652561
13cc0101074
14720162129
1541a797661
hex2745c0d99

10542124441 has 2 divisors, whose sum is σ = 10542124442. Its totient is φ = 10542124440.

The previous prime is 10542124429. The next prime is 10542124513. The reversal of 10542124441 is 14442124501.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9807931225 + 734193216 = 99035^2 + 27096^2 .

It is a cyclic number.

It is not a de Polignac number, because 10542124441 - 227 = 10407906713 is a prime.

It is a super-2 number, since 2×105421244412 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10542124741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5271062220 + 5271062221.

It is an arithmetic number, because the mean of its divisors is an integer number (5271062221).

Almost surely, 210542124441 is an apocalyptic number.

It is an amenable number.

10542124441 is a deficient number, since it is larger than the sum of its proper divisors (1).

10542124441 is an equidigital number, since it uses as much as digits as its factorization.

10542124441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5120, while the sum is 28.

Adding to 10542124441 its reverse (14442124501), we get a palindrome (24984248942).

The spelling of 10542124441 in words is "ten billion, five hundred forty-two million, one hundred twenty-four thousand, four hundred forty-one".