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1054313147 is a prime number
BaseRepresentation
bin111110110101111…
…000101010111011
32201110212122202002
4332311320222323
54124401010042
6252341331215
735061341156
oct7665705273
92643778662
101054313147
114a1150088
12255106b0b
1313a575844
14a0048c9d
156285e132
hex3ed78abb

1054313147 has 2 divisors, whose sum is σ = 1054313148. Its totient is φ = 1054313146.

The previous prime is 1054313137. The next prime is 1054313149. The reversal of 1054313147 is 7413134501.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1054313147 - 212 = 1054309051 is a prime.

It is a super-2 number, since 2×10543131472 = 2223152423874087218, which contains 22 as substring.

Together with 1054313149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1054313149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527156573 + 527156574.

It is an arithmetic number, because the mean of its divisors is an integer number (527156574).

Almost surely, 21054313147 is an apocalyptic number.

1054313147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1054313147 is an equidigital number, since it uses as much as digits as its factorization.

1054313147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 29.

The square root of 1054313147 is about 32470.1885889195. The cubic root of 1054313147 is about 1017.7861593340.

Adding to 1054313147 its reverse (7413134501), we get a palindrome (8467447648).

The spelling of 1054313147 in words is "one billion, fifty-four million, three hundred thirteen thousand, one hundred forty-seven".