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105441307 is a prime number
BaseRepresentation
bin1100100100011…
…10100000011011
321100101222021121
412102032200123
5203443110212
614243550111
72420144026
oct622164033
9240358247
10105441307
1154578684
122b38b337
1318aca40a
141000a1bd
1593cbd07
hex648e81b

105441307 has 2 divisors, whose sum is σ = 105441308. Its totient is φ = 105441306.

The previous prime is 105441263. The next prime is 105441353. The reversal of 105441307 is 703144501.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 105441307 - 215 = 105408539 is a prime.

It is a super-2 number, since 2×1054413072 = 22235738443736498, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (105441377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52720653 + 52720654.

It is an arithmetic number, because the mean of its divisors is an integer number (52720654).

Almost surely, 2105441307 is an apocalyptic number.

105441307 is a deficient number, since it is larger than the sum of its proper divisors (1).

105441307 is an equidigital number, since it uses as much as digits as its factorization.

105441307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1680, while the sum is 25.

The square root of 105441307 is about 10268.4617640618. The cubic root of 105441307 is about 472.4294111770.

Adding to 105441307 its reverse (703144501), we get a palindrome (808585808).

The spelling of 105441307 in words is "one hundred five million, four hundred forty-one thousand, three hundred seven".