Base | Representation |
---|---|
bin | 11110101011111111110… |
… | …10110001010010110101 |
3 | 10201210121212021022111221 |
4 | 33111333322301102311 |
5 | 114233414223201323 |
6 | 2124220220030341 |
7 | 136115224321114 |
oct | 17257772612265 |
9 | 3653555238457 |
10 | 1054413100213 |
11 | 3771a0785500 |
12 | 1504289923b1 |
13 | 7857a407265 |
14 | 39068d01c7b |
15 | 1c66378155d |
hex | f57feb14b5 |
1054413100213 has 48 divisors (see below), whose sum is σ = 1228929831360. Its totient is φ = 901471887360.
The previous prime is 1054413100211. The next prime is 1054413100271. The reversal of 1054413100213 is 3120013144501.
It is not a de Polignac number, because 1054413100213 - 21 = 1054413100211 is a prime.
It is a super-2 number, since 2×10544131002132 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1054413100211) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 181385895 + ... + 181391707.
It is an arithmetic number, because the mean of its divisors is an integer number (25602704820).
Almost surely, 21054413100213 is an apocalyptic number.
It is an amenable number.
1054413100213 is a deficient number, since it is larger than the sum of its proper divisors (174516731147).
1054413100213 is a wasteful number, since it uses less digits than its factorization.
1054413100213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6418 (or 6407 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1054413100213 its reverse (3120013144501), we get a palindrome (4174426244714).
The spelling of 1054413100213 in words is "one trillion, fifty-four billion, four hundred thirteen million, one hundred thousand, two hundred thirteen".
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