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105443163113 is a prime number
BaseRepresentation
bin110001000110011100…
…1101111101111101001
3101002011111220200022112
41202030321233233221
53211421422204423
6120235004532105
710421660045501
oct1421471575751
9332144820275
10105443163113
1140799a0a112
1218528851035
139c35413112
145163d20a01
152b2202da78
hex188ce6fbe9

105443163113 has 2 divisors, whose sum is σ = 105443163114. Its totient is φ = 105443163112.

The previous prime is 105443163109. The next prime is 105443163131. The reversal of 105443163113 is 311361344501.

Together with next prime (105443163131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58203010009 + 47240153104 = 241253^2 + 217348^2 .

It is a cyclic number.

It is not a de Polignac number, because 105443163113 - 22 = 105443163109 is a prime.

It is a super-2 number, since 2×1054431631132 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 105443163113.

It is not a weakly prime, because it can be changed into another prime (105443163613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52721581556 + 52721581557.

It is an arithmetic number, because the mean of its divisors is an integer number (52721581557).

Almost surely, 2105443163113 is an apocalyptic number.

It is an amenable number.

105443163113 is a deficient number, since it is larger than the sum of its proper divisors (1).

105443163113 is an equidigital number, since it uses as much as digits as its factorization.

105443163113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 32.

The spelling of 105443163113 in words is "one hundred five billion, four hundred forty-three million, one hundred sixty-three thousand, one hundred thirteen".