Base | Representation |
---|---|
bin | 110001000111011111… |
… | …1011000111001110011 |
3 | 101002020221211120120101 |
4 | 1202032333120321303 |
5 | 3212004404244401 |
6 | 120242255453231 |
7 | 10422563610616 |
oct | 1421677307163 |
9 | 332227746511 |
10 | 105478196851 |
11 | 40807768515 |
12 | 18538527217 |
13 | 9c3c75b341 |
14 | 516884017d |
15 | 2b2514e101 |
hex | 188efd8e73 |
105478196851 has 2 divisors, whose sum is σ = 105478196852. Its totient is φ = 105478196850.
The previous prime is 105478196833. The next prime is 105478196869. The reversal of 105478196851 is 158691874501.
It is a balanced prime because it is at equal distance from previous prime (105478196833) and next prime (105478196869).
It is a cyclic number.
It is not a de Polignac number, because 105478196851 - 27 = 105478196723 is a prime.
It is a super-2 number, since 2×1054781968512 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 105478196792 and 105478196801.
It is not a weakly prime, because it can be changed into another prime (105478196801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52739098425 + 52739098426.
It is an arithmetic number, because the mean of its divisors is an integer number (52739098426).
Almost surely, 2105478196851 is an apocalyptic number.
105478196851 is a deficient number, since it is larger than the sum of its proper divisors (1).
105478196851 is an equidigital number, since it uses as much as digits as its factorization.
105478196851 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2419200, while the sum is 55.
The spelling of 105478196851 in words is "one hundred five billion, four hundred seventy-eight million, one hundred ninety-six thousand, eight hundred fifty-one".
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