Base | Representation |
---|---|
bin | 110001000111101000… |
… | …1101110100011011101 |
3 | 101002021021212210220120 |
4 | 1202033101232203131 |
5 | 3212012122113000 |
6 | 120242550505153 |
7 | 10422652512162 |
oct | 1421721564335 |
9 | 332237783816 |
10 | 105483004125 |
11 | 4080a451274 |
12 | 1853a0651b9 |
13 | 9c40752495 |
14 | 5169332069 |
15 | 2b2579d6a0 |
hex | 188f46e8dd |
105483004125 has 64 divisors (see below), whose sum is σ = 176971392000. Its totient is φ = 55794816000.
The previous prime is 105483004103. The next prime is 105483004153. The reversal of 105483004125 is 521400384501.
It is not a de Polignac number, because 105483004125 - 224 = 105466226909 is a prime.
It is a super-2 number, since 2×1054830041252 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 56376940 + ... + 56378810.
It is an arithmetic number, because the mean of its divisors is an integer number (2765178000).
Almost surely, 2105483004125 is an apocalyptic number.
105483004125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
105483004125 is a deficient number, since it is larger than the sum of its proper divisors (71488387875).
105483004125 is a wasteful number, since it uses less digits than its factorization.
105483004125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3047 (or 3037 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 105483004125 its reverse (521400384501), we get a palindrome (626883388626).
The spelling of 105483004125 in words is "one hundred five billion, four hundred eighty-three million, four thousand, one hundred twenty-five".
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