Base | Representation |
---|---|
bin | 10011101001110100… |
… | …00100101010110111 |
3 | 1000020100011100022011 |
4 | 21310322010222313 |
5 | 133102114041002 |
6 | 4502555145051 |
7 | 522320461453 |
oct | 116472045267 |
9 | 30210140264 |
10 | 10551315127 |
11 | 4524a40251 |
12 | 2065745187 |
13 | cc1c9b442 |
14 | 721475663 |
15 | 41b4b08d7 |
hex | 274e84ab7 |
10551315127 has 2 divisors, whose sum is σ = 10551315128. Its totient is φ = 10551315126.
The previous prime is 10551315077. The next prime is 10551315139. The reversal of 10551315127 is 72151315501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10551315127 - 211 = 10551313079 is a prime.
It is a super-2 number, since 2×105513151272 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10551615127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5275657563 + 5275657564.
It is an arithmetic number, because the mean of its divisors is an integer number (5275657564).
Almost surely, 210551315127 is an apocalyptic number.
10551315127 is a deficient number, since it is larger than the sum of its proper divisors (1).
10551315127 is an equidigital number, since it uses as much as digits as its factorization.
10551315127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5250, while the sum is 31.
The spelling of 10551315127 in words is "ten billion, five hundred fifty-one million, three hundred fifteen thousand, one hundred twenty-seven".
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