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1055243315033 is a prime number
BaseRepresentation
bin11110101101100010110…
…01110010011101011001
310201212202201110121010222
433112301121302131121
5114242114242040113
62124434434245425
7136144625116355
oct17266131623531
93655681417128
101055243315033
11377587383156
1215061aa26875
1378680408b2b
1439107294465
151c6b15c5e08
hexf5b1672759

1055243315033 has 2 divisors, whose sum is σ = 1055243315034. Its totient is φ = 1055243315032.

The previous prime is 1055243314997. The next prime is 1055243315053. The reversal of 1055243315033 is 3305133425501.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 711006476944 + 344236838089 = 843212^2 + 586717^2 .

It is a cyclic number.

It is not a de Polignac number, because 1055243315033 - 226 = 1055176206169 is a prime.

It is a super-2 number, since 2×10552433150332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1055243314984 and 1055243315002.

It is not a weakly prime, because it can be changed into another prime (1055243315053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527621657516 + 527621657517.

It is an arithmetic number, because the mean of its divisors is an integer number (527621657517).

Almost surely, 21055243315033 is an apocalyptic number.

It is an amenable number.

1055243315033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1055243315033 is an equidigital number, since it uses as much as digits as its factorization.

1055243315033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81000, while the sum is 35.

The spelling of 1055243315033 in words is "one trillion, fifty-five billion, two hundred forty-three million, three hundred fifteen thousand, thirty-three".