Base | Representation |
---|---|
bin | 110001001001001110… |
… | …0011011011100111101 |
3 | 101002101222212110011022 |
4 | 1202102130123130331 |
5 | 3212114223003432 |
6 | 120252125433525 |
7 | 10424166253421 |
oct | 1422234333475 |
9 | 332358773138 |
10 | 105536141117 |
11 | 40837444940 |
12 | 18553a0b8a5 |
13 | 9c4b7686a4 |
14 | 5172404b81 |
15 | 2b2a297b12 |
hex | 189271b73d |
105536141117 has 32 divisors (see below), whose sum is σ = 131049031680. Its totient is φ = 83725505280.
The previous prime is 105536141107. The next prime is 105536141129. The reversal of 105536141117 is 711141635501.
It is a cyclic number.
It is not a de Polignac number, because 105536141117 - 28 = 105536140861 is a prime.
It is a super-2 number, since 2×1055361411172 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (105536141107) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 149003 + ... + 482984.
It is an arithmetic number, because the mean of its divisors is an integer number (4095282240).
Almost surely, 2105536141117 is an apocalyptic number.
105536141117 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
105536141117 is a deficient number, since it is larger than the sum of its proper divisors (25512890563).
105536141117 is a wasteful number, since it uses less digits than its factorization.
105536141117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 632081.
The product of its (nonzero) digits is 12600, while the sum is 35.
Adding to 105536141117 its reverse (711141635501), we get a palindrome (816677776618).
The spelling of 105536141117 in words is "one hundred five billion, five hundred thirty-six million, one hundred forty-one thousand, one hundred seventeen".
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