105540433 has 2 divisors, whose sum is σ = 105540434. Its totient is φ = 105540432.

The previous prime is 105540389. The next prime is 105540451. The reversal of 105540433 is 334045501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57335184 + 48205249 = 7572^2 + 6943^2 .

It is an emirp because it is prime and its reverse (334045501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 105540433 - 2¹⁷ = 105409361 is a prime.

It is a super-2 number, since 2×105540433² = 22277565995654978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 105540398 and 105540407.

It is not a weakly prime, because it can be changed into another prime (105540473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52770216 + 52770217.

It is an arithmetic number, because the mean of its divisors is an integer number (52770217).

Almost surely, 2^105540433 is an apocalyptic number.

It is an amenable number.

105540433 is a deficient number, since it is larger than the sum of its proper divisors (1).

105540433 is an equidigital number, since it uses as much as digits as its factorization.

105540433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600, while the sum is 25.

The square root of 105540433 is about 10273.2873511841. The cubic root of 105540433 is about 472.5774093754.

Adding to 105540433 its reverse (334045501), we get a palindrome (439585934).

The spelling of 105540433 in words is "one hundred five million, five hundred forty thousand, four hundred thirty-three".