Base | Representation |
---|---|
bin | 110001001001011000… |
… | …0100101010001111011 |
3 | 101002102100210212020221 |
4 | 1202102300211101323 |
5 | 3212122101034001 |
6 | 120252435000511 |
7 | 10424262206224 |
oct | 1422260452173 |
9 | 332370725227 |
10 | 105541424251 |
11 | 4083a42316a |
12 | 18555739137 |
13 | 9c4c8982c3 |
14 | 5172dbc24b |
15 | 2b2a98d1a1 |
hex | 1892c2547b |
105541424251 has 2 divisors, whose sum is σ = 105541424252. Its totient is φ = 105541424250.
The previous prime is 105541424203. The next prime is 105541424269. The reversal of 105541424251 is 152424145501.
It is a strong prime.
It is an emirp because it is prime and its reverse (152424145501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 105541424251 - 213 = 105541416059 is a prime.
It is a super-2 number, since 2×1055414242512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (105541404251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52770712125 + 52770712126.
It is an arithmetic number, because the mean of its divisors is an integer number (52770712126).
Almost surely, 2105541424251 is an apocalyptic number.
105541424251 is a deficient number, since it is larger than the sum of its proper divisors (1).
105541424251 is an equidigital number, since it uses as much as digits as its factorization.
105541424251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32000, while the sum is 34.
Adding to 105541424251 its reverse (152424145501), we get a palindrome (257965569752).
The spelling of 105541424251 in words is "one hundred five billion, five hundred forty-one million, four hundred twenty-four thousand, two hundred fifty-one".
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