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10555304413 is a prime number
BaseRepresentation
bin10011101010010010…
…10010100111011101
31000020121200000120111
421311021102213131
5133104124220123
64503220450021
7522366415153
oct116511224735
930217600514
1010555304413
114527215485
122066b49911
13cc2a67174
14721bd33d3
1541b9ec90d
hex2752529dd

10555304413 has 2 divisors, whose sum is σ = 10555304414. Its totient is φ = 10555304412.

The previous prime is 10555304339. The next prime is 10555304423. The reversal of 10555304413 is 31440355501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10261284804 + 294019609 = 101298^2 + 17147^2 .

It is an emirp because it is prime and its reverse (31440355501) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10555304413 is a prime.

It is a super-2 number, since 2×105553044132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10555304423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5277652206 + 5277652207.

It is an arithmetic number, because the mean of its divisors is an integer number (5277652207).

Almost surely, 210555304413 is an apocalyptic number.

It is an amenable number.

10555304413 is a deficient number, since it is larger than the sum of its proper divisors (1).

10555304413 is an equidigital number, since it uses as much as digits as its factorization.

10555304413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 10555304413 its reverse (31440355501), we get a palindrome (41995659914).

The spelling of 10555304413 in words is "ten billion, five hundred fifty-five million, three hundred four thousand, four hundred thirteen".