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105561433 is a prime number
BaseRepresentation
bin1100100101010…
…11110101011001
321100122002001201
412102223311121
5204010431213
614250314201
72421154165
oct622536531
9240562051
10105561433
115464a95a
122b428961
1318b3ccb3
141003bca5
1594026dd
hex64abd59

105561433 has 2 divisors, whose sum is σ = 105561434. Its totient is φ = 105561432.

The previous prime is 105561427. The next prime is 105561439. The reversal of 105561433 is 334165501.

It is a balanced prime because it is at equal distance from previous prime (105561427) and next prime (105561439).

It can be written as a sum of positive squares in only one way, i.e., 77651344 + 27910089 = 8812^2 + 5283^2 .

It is a cyclic number.

It is not a de Polignac number, because 105561433 - 217 = 105430361 is a prime.

It is a super-2 number, since 2×1055614332 = 22286432274026978, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (105561439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52780716 + 52780717.

It is an arithmetic number, because the mean of its divisors is an integer number (52780717).

Almost surely, 2105561433 is an apocalyptic number.

It is an amenable number.

105561433 is a deficient number, since it is larger than the sum of its proper divisors (1).

105561433 is an equidigital number, since it uses as much as digits as its factorization.

105561433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

The square root of 105561433 is about 10274.3093685172. The cubic root of 105561433 is about 472.6087511312.

The spelling of 105561433 in words is "one hundred five million, five hundred sixty-one thousand, four hundred thirty-three".