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105645264433 is a prime number
BaseRepresentation
bin110001001100011110…
…0101100111000110001
3101002200121012111012121
41202120330230320301
53212330141430213
6120311024354241
710426662634252
oct1423074547061
9332617174177
10105645264433
1140892aa78a5
1218584475981
139c682549b7
145182accb29
152b34b5088d
hex1898f2ce31

105645264433 has 2 divisors, whose sum is σ = 105645264434. Its totient is φ = 105645264432.

The previous prime is 105645264421. The next prime is 105645264451. The reversal of 105645264433 is 334462546501.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103792220224 + 1853044209 = 322168^2 + 43047^2 .

It is a cyclic number.

It is not a de Polignac number, because 105645264433 - 217 = 105645133361 is a prime.

It is a super-2 number, since 2×1056452644332 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 105645264433.

It is not a weakly prime, because it can be changed into another prime (105645262433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52822632216 + 52822632217.

It is an arithmetic number, because the mean of its divisors is an integer number (52822632217).

Almost surely, 2105645264433 is an apocalyptic number.

It is an amenable number.

105645264433 is a deficient number, since it is larger than the sum of its proper divisors (1).

105645264433 is an equidigital number, since it uses as much as digits as its factorization.

105645264433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 43.

The spelling of 105645264433 in words is "one hundred five billion, six hundred forty-five million, two hundred sixty-four thousand, four hundred thirty-three".