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10585102941199 is a prime number
BaseRepresentation
bin1001101000001000100101…
…0011001111110000001111
31101110221000000122022102001
42122002021103033300033
52341411242323104244
634302421255413131
72141514501315103
oct232021123176017
941427000568361
1010585102941199
113411131725876
12122b5696841a7
135ba22b6a0127
14288470b07903
151355220325d4
hex9a0894cfc0f

10585102941199 has 2 divisors, whose sum is σ = 10585102941200. Its totient is φ = 10585102941198.

The previous prime is 10585102941173. The next prime is 10585102941233. The reversal of 10585102941199 is 99114920158501.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10585102941199 - 217 = 10585102810127 is a prime.

It is a super-3 number, since 3×105851029411993 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10585102941499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5292551470599 + 5292551470600.

It is an arithmetic number, because the mean of its divisors is an integer number (5292551470600).

Almost surely, 210585102941199 is an apocalyptic number.

10585102941199 is a deficient number, since it is larger than the sum of its proper divisors (1).

10585102941199 is an equidigital number, since it uses as much as digits as its factorization.

10585102941199 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 55.

The spelling of 10585102941199 in words is "ten trillion, five hundred eighty-five billion, one hundred two million, nine hundred forty-one thousand, one hundred ninety-nine".