Base | Representation |
---|---|
bin | 1001101000001000100101… |
… | …0011001111110000001111 |
3 | 1101110221000000122022102001 |
4 | 2122002021103033300033 |
5 | 2341411242323104244 |
6 | 34302421255413131 |
7 | 2141514501315103 |
oct | 232021123176017 |
9 | 41427000568361 |
10 | 10585102941199 |
11 | 3411131725876 |
12 | 122b5696841a7 |
13 | 5ba22b6a0127 |
14 | 288470b07903 |
15 | 1355220325d4 |
hex | 9a0894cfc0f |
10585102941199 has 2 divisors, whose sum is σ = 10585102941200. Its totient is φ = 10585102941198.
The previous prime is 10585102941173. The next prime is 10585102941233. The reversal of 10585102941199 is 99114920158501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10585102941199 - 217 = 10585102810127 is a prime.
It is a super-3 number, since 3×105851029411993 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10585102941499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5292551470599 + 5292551470600.
It is an arithmetic number, because the mean of its divisors is an integer number (5292551470600).
Almost surely, 210585102941199 is an apocalyptic number.
10585102941199 is a deficient number, since it is larger than the sum of its proper divisors (1).
10585102941199 is an equidigital number, since it uses as much as digits as its factorization.
10585102941199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1166400, while the sum is 55.
The spelling of 10585102941199 in words is "ten trillion, five hundred eighty-five billion, one hundred two million, nine hundred forty-one thousand, one hundred ninety-nine".
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