Base | Representation |
---|---|
bin | 11110110110100111010… |
… | …10111011101111111011 |
3 | 10202100100010000111102021 |
4 | 33123103222323233323 |
5 | 114332102434432141 |
6 | 2131002001015311 |
7 | 136406410353142 |
oct | 17332352735773 |
9 | 3670303014367 |
10 | 1060113202171 |
11 | 3796562a1471 |
12 | 151559924537 |
13 | 78c7830c75a |
14 | 39449d66759 |
15 | 1c898dca6d1 |
hex | f6d3abbbfb |
1060113202171 has 2 divisors, whose sum is σ = 1060113202172. Its totient is φ = 1060113202170.
The previous prime is 1060113202163. The next prime is 1060113202199. The reversal of 1060113202171 is 1712023110601.
It is a weak prime.
It is an emirp because it is prime and its reverse (1712023110601) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1060113202171 - 23 = 1060113202163 is a prime.
It is a super-2 number, since 2×10601132021712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1060113202871) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 530056601085 + 530056601086.
It is an arithmetic number, because the mean of its divisors is an integer number (530056601086).
Almost surely, 21060113202171 is an apocalyptic number.
1060113202171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1060113202171 is an equidigital number, since it uses as much as digits as its factorization.
1060113202171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 1060113202171 its reverse (1712023110601), we get a palindrome (2772136312772).
The spelling of 1060113202171 in words is "one trillion, sixty billion, one hundred thirteen million, two hundred two thousand, one hundred seventy-one".
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