Base | Representation |
---|---|
bin | 110001011010000011… |
… | …0011110011001000011 |
3 | 101010212100101200001221 |
4 | 1202310012132121003 |
5 | 3214243301430311 |
6 | 120424140335511 |
7 | 10444164005314 |
oct | 1426406363103 |
9 | 333770350057 |
10 | 106100811331 |
11 | 40aa7161a39 |
12 | 18690b44597 |
13 | a00b744388 |
14 | 51c73d260b |
15 | 2b5eb37671 |
hex | 18b419e643 |
106100811331 has 2 divisors, whose sum is σ = 106100811332. Its totient is φ = 106100811330.
The previous prime is 106100811301. The next prime is 106100811359. The reversal of 106100811331 is 133118001601.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 106100811331 - 219 = 106100287043 is a prime.
It is a super-2 number, since 2×1061008113312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 106100811296 and 106100811305.
It is not a weakly prime, because it can be changed into another prime (106100811301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53050405665 + 53050405666.
It is an arithmetic number, because the mean of its divisors is an integer number (53050405666).
Almost surely, 2106100811331 is an apocalyptic number.
106100811331 is a deficient number, since it is larger than the sum of its proper divisors (1).
106100811331 is an equidigital number, since it uses as much as digits as its factorization.
106100811331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 106100811331 its reverse (133118001601), we get a palindrome (239218812932).
The spelling of 106100811331 in words is "one hundred six billion, one hundred million, eight hundred eleven thousand, three hundred thirty-one".
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