Search a number
-
+
106254422214011 is a prime number
BaseRepresentation
bin11000001010001101001001…
…000101111000010101111011
3111221012211020101010200111022
4120022031021011320111323
5102411333024041322021
61013552335132453055
731244425430611421
oct3012151105702573
9457184211120438
10106254422214011
113094627a3246a5
12bb0099b01a18b
1347399977a49b6
141c34a54871111
15c43dc48e71ab
hex60a34917857b

106254422214011 has 2 divisors, whose sum is σ = 106254422214012. Its totient is φ = 106254422214010.

The previous prime is 106254422213963. The next prime is 106254422214043. The reversal of 106254422214011 is 110412224452601.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (110412224452601) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-106254422214011 is a prime.

It is a super-2 number, since 2×1062544222140112 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (106254422214071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53127211107005 + 53127211107006.

It is an arithmetic number, because the mean of its divisors is an integer number (53127211107006).

Almost surely, 2106254422214011 is an apocalyptic number.

106254422214011 is a deficient number, since it is larger than the sum of its proper divisors (1).

106254422214011 is an equidigital number, since it uses as much as digits as its factorization.

106254422214011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30720, while the sum is 35.

Adding to 106254422214011 its reverse (110412224452601), we get a palindrome (216666646666612).

The spelling of 106254422214011 in words is "one hundred six trillion, two hundred fifty-four billion, four hundred twenty-two million, two hundred fourteen thousand, eleven".