10643440260133 has 2 divisors, whose sum is σ = 10643440260134. Its totient is φ = 10643440260132.

The previous prime is 10643440260121. The next prime is 10643440260143. The reversal of 10643440260133 is 33106204434601.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10416743340004 + 226696920129 = 3227498^2 + 476127^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10643440260133 is a prime.

It is a super-2 number, since 2×10643440260133² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10643440260092 and 10643440260101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10643440260113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5321720130066 + 5321720130067.

It is an arithmetic number, because the mean of its divisors is an integer number (5321720130067).

Almost surely, 2^{10643440260133} is an apocalyptic number.

It is an amenable number.

10643440260133 is a deficient number, since it is larger than the sum of its proper divisors (1).

10643440260133 is an equidigital number, since it uses as much as digits as its factorization.

10643440260133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 37.

Adding to 10643440260133 its reverse (33106204434601), we get a palindrome (43749644694734).

The spelling of 10643440260133 in words is "ten trillion, six hundred forty-three billion, four hundred forty million, two hundred sixty thousand, one hundred thirty-three".