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10650534373 is a prime number
BaseRepresentation
bin10011110101101001…
…00100000111100101
31000111020212012112001
421322310210013211
5133303014044443
64520501525301
7524634022423
oct117264440745
930436765461
1010650534373
114575a49126
122092a13831
1310096ca75b
14730702113
1542505dd4d
hex27ad241e5

10650534373 has 2 divisors, whose sum is σ = 10650534374. Its totient is φ = 10650534372.

The previous prime is 10650534347. The next prime is 10650534413. The reversal of 10650534373 is 37343505601.

10650534373 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5402691009 + 5247843364 = 73503^2 + 72442^2 .

It is a cyclic number.

It is not a de Polignac number, because 10650534373 - 217 = 10650403301 is a prime.

It is a super-2 number, since 2×106505343732 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10650534173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5325267186 + 5325267187.

It is an arithmetic number, because the mean of its divisors is an integer number (5325267187).

Almost surely, 210650534373 is an apocalyptic number.

It is an amenable number.

10650534373 is a deficient number, since it is larger than the sum of its proper divisors (1).

10650534373 is an equidigital number, since it uses as much as digits as its factorization.

10650534373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113400, while the sum is 37.

The spelling of 10650534373 in words is "ten billion, six hundred fifty million, five hundred thirty-four thousand, three hundred seventy-three".