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106633150555433 is a prime number
BaseRepresentation
bin11000001111101101110111…
…000011110110010100101001
3111222120000210121022211121112
4120033231313003312110221
5102434034143020233213
61014442332035320105
731313663606445215
oct3017556703662451
9458500717284545
10106633150555433
1130a81957628077
12bb62276450035
1347666031444c8
141c491018c7945
15c4db8dad1ea8
hex60fb770f6529

106633150555433 has 2 divisors, whose sum is σ = 106633150555434. Its totient is φ = 106633150555432.

The previous prime is 106633150555387. The next prime is 106633150555513. The reversal of 106633150555433 is 334555051336601.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71936656476304 + 34696494079129 = 8481548^2 + 5890373^2 .

It is a cyclic number.

It is not a de Polignac number, because 106633150555433 - 212 = 106633150551337 is a prime.

It is a super-2 number, since 2×1066331505554332 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (106633150555933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53316575277716 + 53316575277717.

It is an arithmetic number, because the mean of its divisors is an integer number (53316575277717).

Almost surely, 2106633150555433 is an apocalyptic number.

It is an amenable number.

106633150555433 is a deficient number, since it is larger than the sum of its proper divisors (1).

106633150555433 is an equidigital number, since it uses as much as digits as its factorization.

106633150555433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7290000, while the sum is 50.

The spelling of 106633150555433 in words is "one hundred six trillion, six hundred thirty-three billion, one hundred fifty million, five hundred fifty-five thousand, four hundred thirty-three".