Base | Representation |
---|---|
bin | 10011111001010100… |
… | …10100000000000011 |
3 | 1000120101221102001022 |
4 | 21330222110000003 |
5 | 133333414320342 |
6 | 4523523300055 |
7 | 525460261541 |
oct | 117452240003 |
9 | 30511842038 |
10 | 10681401347 |
11 | 4591410a21 |
12 | 20a121a62b |
13 | 1012c17236 |
14 | 734858d91 |
15 | 427b099d2 |
hex | 27ca94003 |
10681401347 has 2 divisors, whose sum is σ = 10681401348. Its totient is φ = 10681401346.
The previous prime is 10681401331. The next prime is 10681401371. The reversal of 10681401347 is 74310418601.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10681401347 - 24 = 10681401331 is a prime.
It is a super-2 number, since 2×106814013472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10681401317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5340700673 + 5340700674.
It is an arithmetic number, because the mean of its divisors is an integer number (5340700674).
Almost surely, 210681401347 is an apocalyptic number.
10681401347 is a deficient number, since it is larger than the sum of its proper divisors (1).
10681401347 is an equidigital number, since it uses as much as digits as its factorization.
10681401347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 35.
Adding to 10681401347 its reverse (74310418601), we get a palindrome (84991819948).
The spelling of 10681401347 in words is "ten billion, six hundred eighty-one million, four hundred one thousand, three hundred forty-seven".
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