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10696837590433 is a prime number
BaseRepresentation
bin1001101110101000110100…
…1101000110110110100001
31101212121102000002121012001
42123222031031012312201
52400224110410343213
634430020453004001
72152551415212001
oct233521515066641
941777360077161
1010696837590433
113454559a54595
121249151323601
135c79273887a7
1428da30432001
151383b15751dd
hex9ba8d346da1

10696837590433 has 2 divisors, whose sum is σ = 10696837590434. Its totient is φ = 10696837590432.

The previous prime is 10696837590403. The next prime is 10696837590479. The reversal of 10696837590433 is 33409573869601.

10696837590433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5630070691729 + 5066766898704 = 2372777^2 + 2250948^2 .

It is a cyclic number.

It is not a de Polignac number, because 10696837590433 - 229 = 10696300719521 is a prime.

It is a super-2 number, since 2×106968375904332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10696837590403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5348418795216 + 5348418795217.

It is an arithmetic number, because the mean of its divisors is an integer number (5348418795217).

Almost surely, 210696837590433 is an apocalyptic number.

It is an amenable number.

10696837590433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10696837590433 is an equidigital number, since it uses as much as digits as its factorization.

10696837590433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 88179840, while the sum is 64.

The spelling of 10696837590433 in words is "ten trillion, six hundred ninety-six billion, eight hundred thirty-seven million, five hundred ninety thousand, four hundred thirty-three".