Base | Representation |
---|---|
bin | 10011111101000001… |
… | …01010001111011001 |
3 | 1000122120022121002112 |
4 | 21332200222033121 |
5 | 133414340103213 |
6 | 4530552242105 |
7 | 526315054013 |
oct | 117640521731 |
9 | 30576277075 |
10 | 10712425433 |
11 | 45a7980866 |
12 | 20ab6a0335 |
13 | 101948a398 |
14 | 738a131b3 |
15 | 42a6d6ea8 |
hex | 27e82a3d9 |
10712425433 has 2 divisors, whose sum is σ = 10712425434. Its totient is φ = 10712425432.
The previous prime is 10712425417. The next prime is 10712425487. The reversal of 10712425433 is 33452421701.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8450757184 + 2261668249 = 91928^2 + 47557^2 .
It is a cyclic number.
It is not a de Polignac number, because 10712425433 - 24 = 10712425417 is a prime.
It is a super-2 number, since 2×107124254332 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 10712425433.
It is not a weakly prime, because it can be changed into another prime (10712425403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5356212716 + 5356212717.
It is an arithmetic number, because the mean of its divisors is an integer number (5356212717).
Almost surely, 210712425433 is an apocalyptic number.
It is an amenable number.
10712425433 is a deficient number, since it is larger than the sum of its proper divisors (1).
10712425433 is an equidigital number, since it uses as much as digits as its factorization.
10712425433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 32.
The spelling of 10712425433 in words is "ten billion, seven hundred twelve million, four hundred twenty-five thousand, four hundred thirty-three".
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