Base | Representation |
---|---|
bin | 11000011000000001111000… |
… | …100001001110111000101011 |
3 | 112001120122022100122012220122 |
4 | 120120001320201032320223 |
5 | 103022414110323421203 |
6 | 1020001005111313455 |
7 | 31403156053105466 |
oct | 3030017041167053 |
9 | 461518270565818 |
10 | 107204405685803 |
11 | 31182151218668 |
12 | 10034b2267b88b |
13 | 47a84417646ca |
14 | 1c68a142c42dd |
15 | c5d975101538 |
hex | 61807884ee2b |
107204405685803 has 2 divisors, whose sum is σ = 107204405685804. Its totient is φ = 107204405685802.
The previous prime is 107204405685799. The next prime is 107204405685823. The reversal of 107204405685803 is 308586504402701.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 107204405685803 - 22 = 107204405685799 is a prime.
It is a super-2 number, since 2×1072044056858032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (107204405685823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53602202842901 + 53602202842902.
It is an arithmetic number, because the mean of its divisors is an integer number (53602202842902).
Almost surely, 2107204405685803 is an apocalyptic number.
107204405685803 is a deficient number, since it is larger than the sum of its proper divisors (1).
107204405685803 is an equidigital number, since it uses as much as digits as its factorization.
107204405685803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6451200, while the sum is 53.
The spelling of 107204405685803 in words is "one hundred seven trillion, two hundred four billion, four hundred five million, six hundred eighty-five thousand, eight hundred three".
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