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107555113051 is a prime number
BaseRepresentation
bin110010000101011001…
…0001100100001011011
3101021121200220211222121
41210022302030201123
53230233102104201
6121224331202111
710525213243111
oct1441262144133
9337550824877
10107555113051
114168306a391
1218a17ba6337
13a1b0b26239
1452c45dbab1
152be76569a1
hex190ac8c85b

107555113051 has 2 divisors, whose sum is σ = 107555113052. Its totient is φ = 107555113050.

The previous prime is 107555113019. The next prime is 107555113073. The reversal of 107555113051 is 150311555701.

It is a strong prime.

It is an emirp because it is prime and its reverse (150311555701) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 107555113051 - 25 = 107555113019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 107555112998 and 107555113016.

It is not a weakly prime, because it can be changed into another prime (107555113091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53777556525 + 53777556526.

It is an arithmetic number, because the mean of its divisors is an integer number (53777556526).

Almost surely, 2107555113051 is an apocalyptic number.

107555113051 is a deficient number, since it is larger than the sum of its proper divisors (1).

107555113051 is an equidigital number, since it uses as much as digits as its factorization.

107555113051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13125, while the sum is 34.

Adding to 107555113051 its reverse (150311555701), we get a palindrome (257866668752).

The spelling of 107555113051 in words is "one hundred seven billion, five hundred fifty-five million, one hundred thirteen thousand, fifty-one".