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108026437 is a prime number
BaseRepresentation
bin1100111000001…
…01101001000101
321112021022102011
412130011221011
5210123321222
614415214221
72451131611
oct634055105
9245238364
10108026437
1155a83952
1230217371
13194c3c8c
14104c0341
15973cc77
hex6705a45

108026437 has 2 divisors, whose sum is σ = 108026438. Its totient is φ = 108026436.

The previous prime is 108026407. The next prime is 108026459. The reversal of 108026437 is 734620801.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91126116 + 16900321 = 9546^2 + 4111^2 .

It is an emirp because it is prime and its reverse (734620801) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-108026437 is a prime.

It is a super-2 number, since 2×1080264372 = 23339422181829938, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 108026399 and 108026408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (108026407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54013218 + 54013219.

It is an arithmetic number, because the mean of its divisors is an integer number (54013219).

Almost surely, 2108026437 is an apocalyptic number.

It is an amenable number.

108026437 is a deficient number, since it is larger than the sum of its proper divisors (1).

108026437 is an equidigital number, since it uses as much as digits as its factorization.

108026437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 31.

The square root of 108026437 is about 10393.5767183391. The cubic root of 108026437 is about 476.2591699403.

The spelling of 108026437 in words is "one hundred eight million, twenty-six thousand, four hundred thirty-seven".