1083113 has 2 divisors, whose sum is σ = 1083114. Its totient is φ = 1083112.

The previous prime is 1083107. The next prime is 1083119. The reversal of 1083113 is 3113801.

It is a balanced prime because it is at equal distance from previous prime (1083107) and next prime (1083119).

It can be written as a sum of positive squares in only one way, i.e., 1075369 + 7744 = 1037^2 + 88^2 .

It is an emirp because it is prime and its reverse (3113801) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1083113 - 2¹⁰ = 1082089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1083091 and 1083100.

It is not a weakly prime, because it can be changed into another prime (1083119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 541556 + 541557.

It is an arithmetic number, because the mean of its divisors is an integer number (541557).

2^1083113 is an apocalyptic number.

It is an amenable number.

1083113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1083113 is an equidigital number, since it uses as much as digits as its factorization.

1083113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1083113 is about 1040.7271496411. The cubic root of 1083113 is about 102.6970391857.

Adding to 1083113 its reverse (3113801), we get a palindrome (4196914).

The spelling of 1083113 in words is "one million, eighty-three thousand, one hundred thirteen".