Base | Representation |
---|---|
bin | 101001010101… |
… | …101000001101 |
3 | 202101112212121 |
4 | 221111220031 |
5 | 10233231433 |
6 | 1024132541 |
7 | 161052163 |
oct | 51255015 |
9 | 22345777 |
10 | 10836493 |
11 | 6131688 |
12 | 3767151 |
13 | 2325535 |
14 | 1621233 |
15 | e40c2d |
hex | a55a0d |
10836493 has 4 divisors (see below), whose sum is σ = 10846528. Its totient is φ = 10826460.
The previous prime is 10836491. The next prime is 10836503. The reversal of 10836493 is 39463801.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 39463801 = 13 ⋅3035677.
It is a cyclic number.
It is not a de Polignac number, because 10836493 - 21 = 10836491 is a prime.
It is a Duffinian number.
It is a plaindrome in base 9.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10836491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3171 + ... + 5632.
It is an arithmetic number, because the mean of its divisors is an integer number (2711632).
Almost surely, 210836493 is an apocalyptic number.
It is an amenable number.
10836493 is a deficient number, since it is larger than the sum of its proper divisors (10035).
10836493 is an equidigital number, since it uses as much as digits as its factorization.
10836493 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10034.
The product of its (nonzero) digits is 15552, while the sum is 34.
The square root of 10836493 is about 3291.8828958516. The cubic root of 10836493 is about 221.2905755113.
The spelling of 10836493 in words is "ten million, eight hundred thirty-six thousand, four hundred ninety-three".
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