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1091346590749 is a prime number
BaseRepresentation
bin11111110000110010101…
…00110110110000011101
310212022221211011000211211
433320121110312300131
5120340034211400444
62153205132544421
7141563404651102
oct17703124666035
93768854130754
101091346590749
113909237765a8
12157615922111
137bbb508947c
143ab70112aa9
151d5c5e37c34
hexfe19536c1d

1091346590749 has 2 divisors, whose sum is σ = 1091346590750. Its totient is φ = 1091346590748.

The previous prime is 1091346590729. The next prime is 1091346590759. The reversal of 1091346590749 is 9470956431901.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 733840656025 + 357505934724 = 856645^2 + 597918^2 .

It is a cyclic number.

It is not a de Polignac number, because 1091346590749 - 211 = 1091346588701 is a prime.

It is a super-2 number, since 2×10913465907492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1091346590693 and 1091346590702.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1091346590729) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 545673295374 + 545673295375.

It is an arithmetic number, because the mean of its divisors is an integer number (545673295375).

Almost surely, 21091346590749 is an apocalyptic number.

It is an amenable number.

1091346590749 is a deficient number, since it is larger than the sum of its proper divisors (1).

1091346590749 is an equidigital number, since it uses as much as digits as its factorization.

1091346590749 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7348320, while the sum is 58.

The spelling of 1091346590749 in words is "one trillion, ninety-one billion, three hundred forty-six million, five hundred ninety thousand, seven hundred forty-nine".