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109142052497081 is a prime number
BaseRepresentation
bin11000110100001110011101…
…010001001110011010111001
3112022102212201021221220001122
4120310032131101032122321
5103301140410414401311
61024043100003155025
731663152543206402
oct3064163521163271
9468385637856048
10109142052497081
113185998034191a
12102a8564675a75
1348b9088b92b26
141cd47099689a9
15c9407dea00db
hex63439d44e6b9

109142052497081 has 2 divisors, whose sum is σ = 109142052497082. Its totient is φ = 109142052497080.

The previous prime is 109142052497069. The next prime is 109142052497113. The reversal of 109142052497081 is 180794250241901.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108911849255056 + 230203242025 = 10436084^2 + 479795^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-109142052497081 is a prime.

It is a super-2 number, since 2×1091420524970812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (109142052497381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54571026248540 + 54571026248541.

It is an arithmetic number, because the mean of its divisors is an integer number (54571026248541).

Almost surely, 2109142052497081 is an apocalyptic number.

It is an amenable number.

109142052497081 is a deficient number, since it is larger than the sum of its proper divisors (1).

109142052497081 is an equidigital number, since it uses as much as digits as its factorization.

109142052497081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 53.

The spelling of 109142052497081 in words is "one hundred nine trillion, one hundred forty-two billion, fifty-two million, four hundred ninety-seven thousand, eighty-one".