Base | Representation |
---|---|
bin | 11000110100001110011101… |
… | …010001001110011101011011 |
3 | 112022102212201021221220021122 |
4 | 120310032131101032131123 |
5 | 103301140410414402433 |
6 | 1024043100003155455 |
7 | 31663152543210023 |
oct | 3064163521163533 |
9 | 468385637856248 |
10 | 109142052497243 |
11 | 31859980341a57 |
12 | 102a8564675b8b |
13 | 48b9088b92c1c |
14 | 1cd4709968a83 |
15 | c9407dea0198 |
hex | 63439d44e75b |
109142052497243 has 2 divisors, whose sum is σ = 109142052497244. Its totient is φ = 109142052497242.
The previous prime is 109142052497209. The next prime is 109142052497267. The reversal of 109142052497243 is 342794250241901.
It is a strong prime.
It is an emirp because it is prime and its reverse (342794250241901) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 109142052497243 - 222 = 109142048302939 is a prime.
It is not a weakly prime, because it can be changed into another prime (109142052497293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54571026248621 + 54571026248622.
It is an arithmetic number, because the mean of its divisors is an integer number (54571026248622).
Almost surely, 2109142052497243 is an apocalyptic number.
109142052497243 is a deficient number, since it is larger than the sum of its proper divisors (1).
109142052497243 is an equidigital number, since it uses as much as digits as its factorization.
109142052497243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4354560, while the sum is 53.
The spelling of 109142052497243 in words is "one hundred nine trillion, one hundred forty-two billion, fifty-two million, four hundred ninety-seven thousand, two hundred forty-three".
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