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109142052497243 is a prime number
BaseRepresentation
bin11000110100001110011101…
…010001001110011101011011
3112022102212201021221220021122
4120310032131101032131123
5103301140410414402433
61024043100003155455
731663152543210023
oct3064163521163533
9468385637856248
10109142052497243
1131859980341a57
12102a8564675b8b
1348b9088b92c1c
141cd4709968a83
15c9407dea0198
hex63439d44e75b

109142052497243 has 2 divisors, whose sum is σ = 109142052497244. Its totient is φ = 109142052497242.

The previous prime is 109142052497209. The next prime is 109142052497267. The reversal of 109142052497243 is 342794250241901.

It is a strong prime.

It is an emirp because it is prime and its reverse (342794250241901) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 109142052497243 - 222 = 109142048302939 is a prime.

It is not a weakly prime, because it can be changed into another prime (109142052497293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54571026248621 + 54571026248622.

It is an arithmetic number, because the mean of its divisors is an integer number (54571026248622).

Almost surely, 2109142052497243 is an apocalyptic number.

109142052497243 is a deficient number, since it is larger than the sum of its proper divisors (1).

109142052497243 is an equidigital number, since it uses as much as digits as its factorization.

109142052497243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4354560, while the sum is 53.

The spelling of 109142052497243 in words is "one hundred nine trillion, one hundred forty-two billion, fifty-two million, four hundred ninety-seven thousand, two hundred forty-three".