10920113 has 2 divisors, whose sum is σ = 10920114. Its totient is φ = 10920112.

The previous prime is 10920097. The next prime is 10920131. The reversal of 10920113 is 31102901.

It is a happy number.

Together with next prime (10920131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10291264 + 628849 = 3208^2 + 793^2 .

It is an emirp because it is prime and its reverse (31102901) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10920113 - 2⁴ = 10920097 is a prime.

It is a super-3 number, since 3×10920113³ (a number of 22 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10920091 and 10920100.

It is not a weakly prime, because it can be changed into another prime (10920913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5460056 + 5460057.

It is an arithmetic number, because the mean of its divisors is an integer number (5460057).

Almost surely, 2^10920113 is an apocalyptic number.

It is an amenable number.

10920113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10920113 is an equidigital number, since it uses as much as digits as its factorization.

10920113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

The square root of 10920113 is about 3304.5594260052. The cubic root of 10920113 is about 221.8583152963.

The spelling of 10920113 in words is "ten million, nine hundred twenty thousand, one hundred thirteen".