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10929478979 is a prime number
BaseRepresentation
bin10100010110111001…
…01001110101000011
31001012200202001120202
422023130221311003
5134340421311404
65004304355415
7534562016126
oct121334516503
931180661522
1010929478979
1146a9451361
122150315b6b
131052435933
147597943bd
1543e7ae21e
hex28b729d43

10929478979 has 2 divisors, whose sum is σ = 10929478980. Its totient is φ = 10929478978.

The previous prime is 10929478969. The next prime is 10929478981. The reversal of 10929478979 is 97987492901.

10929478979 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (97987492901) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10929478979 is a prime.

It is a super-3 number, since 3×109294789793 (a number of 31 digits) contains 333 as substring.

Together with 10929478981, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10929478949) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5464739489 + 5464739490.

It is an arithmetic number, because the mean of its divisors is an integer number (5464739490).

Almost surely, 210929478979 is an apocalyptic number.

10929478979 is a deficient number, since it is larger than the sum of its proper divisors (1).

10929478979 is an equidigital number, since it uses as much as digits as its factorization.

10929478979 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20575296, while the sum is 65.

The spelling of 10929478979 in words is "ten billion, nine hundred twenty-nine million, four hundred seventy-eight thousand, nine hundred seventy-nine".