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109325656981 is a prime number
BaseRepresentation
bin110010111010001010…
…0010010001110010101
3101110012002111210122201
41211310110102032111
53242344332010411
6122120140124501
710620122515552
oct1456424221625
9343162453581
10109325656981
1142401535232
1219230b36731
13a4038a1a78
145411807a29
152c9cce23c1
hex1974512395

109325656981 has 2 divisors, whose sum is σ = 109325656982. Its totient is φ = 109325656980.

The previous prime is 109325656969. The next prime is 109325656987. The reversal of 109325656981 is 189656523901.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84160911025 + 25164745956 = 290105^2 + 158634^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-109325656981 is a prime.

It is a super-2 number, since 2×1093256569812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (109325656987) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54662828490 + 54662828491.

It is an arithmetic number, because the mean of its divisors is an integer number (54662828491).

Almost surely, 2109325656981 is an apocalyptic number.

It is an amenable number.

109325656981 is a deficient number, since it is larger than the sum of its proper divisors (1).

109325656981 is an equidigital number, since it uses as much as digits as its factorization.

109325656981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3499200, while the sum is 55.

The spelling of 109325656981 in words is "one hundred nine billion, three hundred twenty-five million, six hundred fifty-six thousand, nine hundred eighty-one".