10940131 has 2 divisors, whose sum is σ = 10940132. Its totient is φ = 10940130.

The previous prime is 10940119. The next prime is 10940159. The reversal of 10940131 is 13104901.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (13104901) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10940131 is a prime.

It is a super-2 number, since 2×10940131² = 239372932594322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10940099 and 10940108.

It is not a weakly prime, because it can be changed into another prime (10940191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5470065 + 5470066.

It is an arithmetic number, because the mean of its divisors is an integer number (5470066).

Almost surely, 2^10940131 is an apocalyptic number.

10940131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10940131 is an equidigital number, since it uses as much as digits as its factorization.

10940131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

The square root of 10940131 is about 3307.5868847243. The cubic root of 10940131 is about 221.9937976786.

The spelling of 10940131 in words is "ten million, nine hundred forty thousand, one hundred thirty-one".