Base | Representation |
---|---|
bin | 110010111101010111… |
… | …1101011101100110101 |
3 | 101110110121102220220211 |
4 | 1211322233223230311 |
5 | 3243104434040032 |
6 | 122134551425421 |
7 | 10622602265203 |
oct | 1457257535465 |
9 | 343417386824 |
10 | 109433502517 |
11 | 424573a5179 |
12 | 19261085271 |
13 | a4200315b1 |
14 | 5421c7c073 |
15 | 2ca74e6747 |
hex | 197abebb35 |
109433502517 has 2 divisors, whose sum is σ = 109433502518. Its totient is φ = 109433502516.
The previous prime is 109433502509. The next prime is 109433502523. The reversal of 109433502517 is 715205334901.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105291164196 + 4142338321 = 324486^2 + 64361^2 .
It is a cyclic number.
It is not a de Polignac number, because 109433502517 - 23 = 109433502509 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 109433502517.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (109433502557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54716751258 + 54716751259.
It is an arithmetic number, because the mean of its divisors is an integer number (54716751259).
Almost surely, 2109433502517 is an apocalyptic number.
It is an amenable number.
109433502517 is a deficient number, since it is larger than the sum of its proper divisors (1).
109433502517 is an equidigital number, since it uses as much as digits as its factorization.
109433502517 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 40.
The spelling of 109433502517 in words is "one hundred nine billion, four hundred thirty-three million, five hundred two thousand, five hundred seventeen".
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