Base | Representation |
---|---|
bin | 10100011001101100… |
… | …01100100010111001 |
3 | 1001021022220121111122 |
4 | 22030312030202321 |
5 | 134412423430433 |
6 | 5010503435025 |
7 | 535265361434 |
oct | 121466144271 |
9 | 31238817448 |
10 | 10952951993 |
11 | 4710723a45 |
12 | 2158155a75 |
13 | 1057263aa9 |
14 | 75c94481b |
15 | 441899198 |
hex | 28cd8c8b9 |
10952951993 has 2 divisors, whose sum is σ = 10952951994. Its totient is φ = 10952951992.
The previous prime is 10952951939. The next prime is 10952952067. The reversal of 10952951993 is 39915925901.
Together with previous prime (10952951939) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8373531049 + 2579420944 = 91507^2 + 50788^2 .
It is a cyclic number.
It is not a de Polignac number, because 10952951993 - 228 = 10684516537 is a prime.
It is not a weakly prime, because it can be changed into another prime (10952954993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5476475996 + 5476475997.
It is an arithmetic number, because the mean of its divisors is an integer number (5476475997).
Almost surely, 210952951993 is an apocalyptic number.
It is an amenable number.
10952951993 is a deficient number, since it is larger than the sum of its proper divisors (1).
10952951993 is an equidigital number, since it uses as much as digits as its factorization.
10952951993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 984150, while the sum is 53.
The spelling of 10952951993 in words is "ten billion, nine hundred fifty-two million, nine hundred fifty-one thousand, nine hundred ninety-three".
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