1095444013 has 2 divisors, whose sum is σ = 1095444014. Its totient is φ = 1095444012.

The previous prime is 1095443983. The next prime is 1095444017. The reversal of 1095444013 is 3104445901.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 788598724 + 306845289 = 28082^2 + 17517^2 .

It is an emirp because it is prime and its reverse (3104445901) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1095444013 - 2⁵ = 1095443981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1095444017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 547722006 + 547722007.

It is an arithmetic number, because the mean of its divisors is an integer number (547722007).

Almost surely, 2^1095444013 is an apocalyptic number.

It is an amenable number.

1095444013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1095444013 is an equidigital number, since it uses as much as digits as its factorization.

1095444013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

The square root of 1095444013 is about 33097.4925485300. The cubic root of 1095444013 is about 1030.8529752092.

Adding to 1095444013 its reverse (3104445901), we get a palindrome (4199889914).

The spelling of 1095444013 in words is "one billion, ninety-five million, four hundred forty-four thousand, thirteen".