Base | Representation |
---|---|
bin | 11111111101011101101… |
… | …01111001000011101001 |
3 | 10212222111222000012220221 |
4 | 33332232311321003221 |
5 | 120443002401222101 |
6 | 2200252210050041 |
7 | 142224116120524 |
oct | 17765665710351 |
9 | 3788458005827 |
10 | 1098150023401 |
11 | 3937a5072212 |
12 | 1589b4279921 |
13 | 7c72a73a672 |
14 | 3b217901bbb |
15 | 1d873374aa1 |
hex | ffaed790e9 |
1098150023401 has 2 divisors, whose sum is σ = 1098150023402. Its totient is φ = 1098150023400.
The previous prime is 1098150023363. The next prime is 1098150023473. The reversal of 1098150023401 is 1043200518901.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 796111847001 + 302038176400 = 892251^2 + 549580^2 .
It is an emirp because it is prime and its reverse (1043200518901) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1098150023401 - 29 = 1098150022889 is a prime.
It is not a weakly prime, because it can be changed into another prime (1098150023701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 549075011700 + 549075011701.
It is an arithmetic number, because the mean of its divisors is an integer number (549075011701).
Almost surely, 21098150023401 is an apocalyptic number.
It is an amenable number.
1098150023401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1098150023401 is an equidigital number, since it uses as much as digits as its factorization.
1098150023401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 34.
The spelling of 1098150023401 in words is "one trillion, ninety-eight billion, one hundred fifty million, twenty-three thousand, four hundred one".
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