Base | Representation |
---|---|
bin | 110011001100001110… |
… | …0010100100011100001 |
3 | 101111202022222011222222 |
4 | 1212120130110203201 |
5 | 3300120011242312 |
6 | 122300230440425 |
7 | 10641132254534 |
oct | 1463034244341 |
9 | 344668864888 |
10 | 109931743457 |
11 | 4269266aa48 |
12 | 1937bb03115 |
13 | a49c31bb13 |
14 | 546c0d6a1b |
15 | 2cd6113672 |
hex | 19987148e1 |
109931743457 has 2 divisors, whose sum is σ = 109931743458. Its totient is φ = 109931743456.
The previous prime is 109931743447. The next prime is 109931743507. The reversal of 109931743457 is 754347139901.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 101623238656 + 8308504801 = 318784^2 + 91151^2 .
It is a cyclic number.
It is not a de Polignac number, because 109931743457 - 218 = 109931481313 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 109931743399 and 109931743408.
It is not a weakly prime, because it can be changed into another prime (109931743447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54965871728 + 54965871729.
It is an arithmetic number, because the mean of its divisors is an integer number (54965871729).
Almost surely, 2109931743457 is an apocalyptic number.
It is an amenable number.
109931743457 is a deficient number, since it is larger than the sum of its proper divisors (1).
109931743457 is an equidigital number, since it uses as much as digits as its factorization.
109931743457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2857680, while the sum is 53.
The spelling of 109931743457 in words is "one hundred nine billion, nine hundred thirty-one million, seven hundred forty-three thousand, four hundred fifty-seven".
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