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109931745493 is a prime number
BaseRepresentation
bin110011001100001110…
…0010101000011010101
3101111202022222021210101
41212120130111003111
53300120011323433
6122300230454101
710641132263503
oct1463034250325
9344668867711
10109931745493
1142692671529
121937bb04331
13a49c31ca1b
14546c0d7673
152cd611407d
hex19987150d5

109931745493 has 2 divisors, whose sum is σ = 109931745494. Its totient is φ = 109931745492.

The previous prime is 109931745431. The next prime is 109931745499. The reversal of 109931745493 is 394547139901.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101466457444 + 8465288049 = 318538^2 + 92007^2 .

It is an emirp because it is prime and its reverse (394547139901) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 109931745493 - 29 = 109931744981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (109931745499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54965872746 + 54965872747.

It is an arithmetic number, because the mean of its divisors is an integer number (54965872747).

Almost surely, 2109931745493 is an apocalyptic number.

It is an amenable number.

109931745493 is a deficient number, since it is larger than the sum of its proper divisors (1).

109931745493 is an equidigital number, since it uses as much as digits as its factorization.

109931745493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3674160, while the sum is 55.

The spelling of 109931745493 in words is "one hundred nine billion, nine hundred thirty-one million, seven hundred forty-five thousand, four hundred ninety-three".