1100000000081 has 2 divisors, whose sum is σ = 1100000000082. Its totient is φ = 1100000000080.

The previous prime is 1100000000041. The next prime is 1100000000119. The reversal of 1100000000081 is 1800000000011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 913735251025 + 186264749056 = 955895^2 + 431584^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100000000081 - 2¹⁴ = 1099999983697 is a prime.

It is a super-2 number, since 2×1100000000081² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1099999999990 and 1100000000071.

It is not a weakly prime, because it can be changed into another prime (1100000000041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550000000040 + 550000000041.

It is an arithmetic number, because the mean of its divisors is an integer number (550000000041).

Almost surely, 2^{1100000000081} is an apocalyptic number.

It is an amenable number.

1100000000081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100000000081 is an equidigital number, since it uses as much as digits as its factorization.

1100000000081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 1100000000081 its reverse (1800000000011), we get a palindrome (2900000000092).

The spelling of 1100000000081 in words is "one trillion, one hundred billion, eighty-one", and thus it is an aban number.