1100000000119 has 2 divisors, whose sum is σ = 1100000000120. Its totient is φ = 1100000000118.

The previous prime is 1100000000081. The next prime is 1100000000147. The reversal of 1100000000119 is 9110000000011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1100000000119 - 2⁹ = 1099999999607 is a prime.

It is a super-2 number, since 2×1100000000119² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100000000099 and 1100000000108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100000000219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550000000059 + 550000000060.

It is an arithmetic number, because the mean of its divisors is an integer number (550000000060).

Almost surely, 2^{1100000000119} is an apocalyptic number.

1100000000119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100000000119 is an equidigital number, since it uses as much as digits as its factorization.

1100000000119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 13.

It can be divided in two parts, 110000000011 and 9, that multiplied together give a palindrome (990000000099).

The spelling of 1100000000119 in words is "one trillion, one hundred billion, one hundred nineteen", and thus it is an aban number.