110000014013 has 2 divisors, whose sum is σ = 110000014014. Its totient is φ = 110000014012.

The previous prime is 110000013997. The next prime is 110000014027. The reversal of 110000014013 is 310410000011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105249634084 + 4750379929 = 324422^2 + 68923^2 .

It is a cyclic number.

It is not a de Polignac number, because 110000014013 - 2⁴ = 110000013997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110000013985 and 110000014003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110000014043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000007006 + 55000007007.

It is an arithmetic number, because the mean of its divisors is an integer number (55000007007).

Almost surely, 2^110000014013 is an apocalyptic number.

It is an amenable number.

110000014013 is a deficient number, since it is larger than the sum of its proper divisors (1).

110000014013 is an equidigital number, since it uses as much as digits as its factorization.

110000014013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 110000014013 its reverse (310410000011), we get a palindrome (420410014024).

The spelling of 110000014013 in words is "one hundred ten billion, fourteen thousand, thirteen".